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Voltage Divider Calculator

Enter the input voltage and the two resistors to get the output voltage, current and power, with a live circuit diagram that updates as you type. Formula: Vout = Vin × R2 ÷ (R1 + R2).

होमैये: Vout = Vin × R2 ÷ (R1 + R2). सापेट डालें, नॆटडाइट्राप सादे सादा आसानी सादी सादे यॆसीने पासा पॆच्ता है एह युजैल दालें। सापेट लाइन सादे सादी दालें। पाता है एदा दालें।

Formula: Vout = Vin × R2 ÷ (R1 + R2). Values dalo, live circuit diagram apne aap update hota rahega.

Quick answer: Vin = 5 V with R1 = 5 kΩ and R2 = 5 kΩ (to ground) gives Vout = 2.5 V — exactly half: Vout = 5 × 5000 ÷ (5000 + 5000) = 2.5.
R2 always connects to ground
Output Vout
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Divider current
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Power in R1
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Power in R2
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Vin = 5 V R1 = 5 kΩ P1 = 1.25 mW Vout = 2.5 V I = 0.5 mA R2 = 5 kΩ P2 = 1.25 mW

How the voltage divider works

Vout = Vin × R2 ÷ (R1 + R2)

Two resistors in series divide the input voltage in proportion to their resistance. The output is taken at the point between them:

Worked examples

InputR1R2OutputUse case
5 V5 kΩ5 kΩ2.5 VHalf voltage, balanced divider
5 V10 kΩ20 kΩ3.33 V5 V logic to 3.3 V input (Arduino to ESP32/Raspberry Pi)
12 V14 kΩ10 kΩ5 V12 V battery to 5 V sensor reading
9 V1 kΩ1 kΩ4.5 VBattery midpoint reference
14.4 V4.7 kΩ1 kΩ2.55 VCar battery voltage into a microcontroller ADC

Real uses of a voltage divider

Important: a divider is for signals and references only. The moment a load draws real current from the output, the voltage sags — see the next section. To power something, use a regulator or buck converter instead.

Why the output drops when you connect a load

A load connected to the output acts like a third resistor in parallel with R2. The combined resistance is smaller than R2, so the divider ratio shifts and Vout falls. Rule of thumb: keep the load resistance at least 10× larger than R2, or buffer the output with an op-amp or emitter follower.

FAQ

What is the voltage divider formula?

Vout = Vin × R2 ÷ (R1 + R2). With 5 V in and 5 kΩ + 5 kΩ: Vout = 5 × 5000 ÷ 10000 = 2.5 V.

How do I convert 5 V to 3.3 V with resistors?

You need a ratio of 0.66. Use R1 = 10 kΩ, R2 = 20 kΩ: Vout = 5 × 20000 ÷ 30000 = 3.33 V. Fine for a 5 V logic output feeding a 3.3 V high-impedance input. It cannot power a device.

Can I power a device from a divider?

No. Any load current pulls the output voltage down. Use a regulator (78XX, LDO, buck module) for powering.

How much current flows?

I = Vin ÷ (R1 + R2). 5 V across 10 kΩ total = 0.5 mA. Smaller resistors give a stiffer divider but waste more current.

What power rating do I need?

P = I² × R for each resistor. The 5 V / 10 kΩ example dissipates 1.25 mW per resistor — any resistor handles that. Check power for low-ohm or high-voltage dividers.

Does it work for AC?

Yes — resistive dividers divide AC and DC alike at any instant. At high frequencies stray capacitance matters.

About this tool

Built by Sayan Roy Chowdhury, the engineer behind Byte Sherlock in Barrackpore, West Bengal. Voltage dividers come up daily in repair work — battery sense lines, level-shifted signals, dead-board tracing. If your board is beyond a calculator, that is our job: see laptop repair or mobile repair.

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